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(x^2-1)+(5x+25)=90
We move all terms to the left:
(x^2-1)+(5x+25)-(90)=0
We get rid of parentheses
x^2+5x-1+25-90=0
We add all the numbers together, and all the variables
x^2+5x-66=0
a = 1; b = 5; c = -66;
Δ = b2-4ac
Δ = 52-4·1·(-66)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-17}{2*1}=\frac{-22}{2} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+17}{2*1}=\frac{12}{2} =6 $
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